150240400211533 has 2 divisors, whose sum is σ = 150240400211534. Its totient is φ = 150240400211532.

The previous prime is 150240400211491. The next prime is 150240400211579. The reversal of 150240400211533 is 335112004042051.

150240400211533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 118543252491049 + 31697147720484 = 10887757^2 + 5630022^2 .

It is a cyclic number.

It is not a de Polignac number, because 150240400211533 - 2⁴⁵ = 115056028122701 is a prime.

It is a super-2 number, since 2×150240400211533² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150240400211495 and 150240400211504.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (150240400611533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75120200105766 + 75120200105767.

It is an arithmetic number, because the mean of its divisors is an integer number (75120200105767).

Almost surely, 2^{150240400211533} is an apocalyptic number.

It is an amenable number.

150240400211533 is a deficient number, since it is larger than the sum of its proper divisors (1).

150240400211533 is an equidigital number, since it uses as much as digits as its factorization.

150240400211533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 150240400211533 its reverse (335112004042051), we get a palindrome (485352404253584).

The spelling of 150240400211533 in words is "one hundred fifty trillion, two hundred forty billion, four hundred million, two hundred eleven thousand, five hundred thirty-three".