150254014113 has 24 divisors (see below), whose sum is σ = 248611254528. Its totient is φ = 85661131392.

The previous prime is 150254014087. The next prime is 150254014139. The reversal of 150254014113 is 311410452051.

150254014113 is a `hidden beast` number, since 1 + 5 + 0 + 2 + 540 + 1 + 4 + 113 = 666.

It is an interprime number because it is at equal distance from previous prime (150254014087) and next prime (150254014139).

It is not a de Polignac number, because 150254014113 - 2⁵ = 150254014081 is a prime.

It is a super-3 number, since 3×150254014113³ (a number of 35 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (150254014153) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2726745 + ... + 2781302.

It is an arithmetic number, because the mean of its divisors is an integer number (10358802272).

Almost surely, 2^150254014113 is an apocalyptic number.

It is an amenable number.

150254014113 is a deficient number, since it is larger than the sum of its proper divisors (98357240415).

150254014113 is a wasteful number, since it uses less digits than its factorization.

150254014113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5508493 (or 5508490 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 150254014113 its reverse (311410452051), we get a palindrome (461664466164).

The spelling of 150254014113 in words is "one hundred fifty billion, two hundred fifty-four million, fourteen thousand, one hundred thirteen".