Base | Representation |
---|---|
bin | 1000101111111111000… |
… | …1111101010010010111 |
3 | 112101000001221001100102 |
4 | 2023333301331102113 |
5 | 4430323431033411 |
6 | 153020043004315 |
7 | 13601034253553 |
oct | 2137761752227 |
9 | 471001831312 |
10 | 150320174231 |
11 | 58828901857 |
12 | 25171b0969b |
13 | 112379c1a76 |
14 | 73c00d6863 |
15 | 3d9bc75d3b |
hex | 22ffc7d497 |
150320174231 has 2 divisors, whose sum is σ = 150320174232. Its totient is φ = 150320174230.
The previous prime is 150320174219. The next prime is 150320174287. The reversal of 150320174231 is 132471023051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150320174231 - 26 = 150320174167 is a prime.
It is a super-2 number, since 2×1503201742312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 150320174194 and 150320174203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150320174531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75160087115 + 75160087116.
It is an arithmetic number, because the mean of its divisors is an integer number (75160087116).
Almost surely, 2150320174231 is an apocalyptic number.
150320174231 is a deficient number, since it is larger than the sum of its proper divisors (1).
150320174231 is an equidigital number, since it uses as much as digits as its factorization.
150320174231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 29.
Adding to 150320174231 its reverse (132471023051), we get a palindrome (282791197282).
The spelling of 150320174231 in words is "one hundred fifty billion, three hundred twenty million, one hundred seventy-four thousand, two hundred thirty-one".
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