Base | Representation |
---|---|
bin | 11100000000001100… |
… | …01011010101011111 |
3 | 1102210202010120112202 |
4 | 32000012023111133 |
5 | 221242201123311 |
6 | 10523450522115 |
7 | 1041361634606 |
oct | 160006132537 |
9 | 42722116482 |
10 | 15034004831 |
11 | 641533838a |
12 | 2ab6a3633b |
13 | 15578c3b61 |
14 | a28956a3d |
15 | 5ceccee3b |
hex | 38018b55f |
15034004831 has 2 divisors, whose sum is σ = 15034004832. Its totient is φ = 15034004830.
The previous prime is 15034004779. The next prime is 15034004849. The reversal of 15034004831 is 13840043051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15034004831 - 210 = 15034003807 is a prime.
It is a super-2 number, since 2×150340048312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15034004794 and 15034004803.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15034004891) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7517002415 + 7517002416.
It is an arithmetic number, because the mean of its divisors is an integer number (7517002416).
Almost surely, 215034004831 is an apocalyptic number.
15034004831 is a deficient number, since it is larger than the sum of its proper divisors (1).
15034004831 is an equidigital number, since it uses as much as digits as its factorization.
15034004831 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 15034004831 its reverse (13840043051), we get a palindrome (28874047882).
The spelling of 15034004831 in words is "fifteen billion, thirty-four million, four thousand, eight hundred thirty-one".
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