Base | Representation |
---|---|
bin | 100010001011110000001010… |
… | …000001111001111111110010 |
3 | 201201022110220222001112201211 |
4 | 202023300022001321333302 |
5 | 124201142241044013132 |
6 | 1251425443451150334 |
7 | 43444536113516161 |
oct | 4213601201717762 |
9 | 651273828045654 |
10 | 150341203501042 |
11 | 439a3389a97764 |
12 | 14a41170a453aa |
13 | 65b7164b98c68 |
14 | 291a7a58cb3d8 |
15 | 125aabe0a3147 |
hex | 88bc0a079ff2 |
150341203501042 has 4 divisors (see below), whose sum is σ = 225511805251566. Its totient is φ = 75170601750520.
The previous prime is 150341203501007. The next prime is 150341203501051. The reversal of 150341203501042 is 240105302143051.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 135950492967961 + 14390710533081 = 11659781^2 + 3793509^2 .
It is a junction number, because it is equal to n+sod(n) for n = 150341203500995 and 150341203501013.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37585300875259 + ... + 37585300875262.
Almost surely, 2150341203501042 is an apocalyptic number.
150341203501042 is a deficient number, since it is larger than the sum of its proper divisors (75170601750524).
150341203501042 is an equidigital number, since it uses as much as digits as its factorization.
150341203501042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75170601750523.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 150341203501042 its reverse (240105302143051), we get a palindrome (390446505644093).
The spelling of 150341203501042 in words is "one hundred fifty trillion, three hundred forty-one billion, two hundred three million, five hundred one thousand, forty-two".
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