Base | Representation |
---|---|
bin | 1000110000000101100… |
… | …1111110000100000111 |
3 | 112101001222020022111012 |
4 | 2030001121332010013 |
5 | 4430402421043031 |
6 | 153022455232435 |
7 | 13601515105001 |
oct | 2140131760407 |
9 | 471058208435 |
10 | 150347440391 |
11 | 58842235275 |
12 | 2517b07871b |
13 | 1124054a5a5 |
14 | 73c3993371 |
15 | 3d9e35eb2b |
hex | 230167e107 |
150347440391 has 2 divisors, whose sum is σ = 150347440392. Its totient is φ = 150347440390.
The previous prime is 150347440319. The next prime is 150347440457. The reversal of 150347440391 is 193044743051.
Together with previous prime (150347440319) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 150347440391 - 222 = 150343246087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150347440091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75173720195 + 75173720196.
It is an arithmetic number, because the mean of its divisors is an integer number (75173720196).
Almost surely, 2150347440391 is an apocalyptic number.
150347440391 is a deficient number, since it is larger than the sum of its proper divisors (1).
150347440391 is an equidigital number, since it uses as much as digits as its factorization.
150347440391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 41.
The spelling of 150347440391 in words is "one hundred fifty billion, three hundred forty-seven million, four hundred forty thousand, three hundred ninety-one".
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