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150350024033 = 1113668184003
BaseRepresentation
bin1000110000000110001…
…1110100110101100001
3112101002011002120120122
42030001203310311201
54430404101232113
6153023030450025
713601546055326
oct2140143646541
9471064076518
10150350024033
115884373a410
122517bb03915
1311240c43581
1473c4066b4d
153d9e6c0408
hex23018f4d61

150350024033 has 4 divisors (see below), whose sum is σ = 164018208048. Its totient is φ = 136681840020.

The previous prime is 150350023997. The next prime is 150350024129. The reversal of 150350024033 is 330420053051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a de Polignac number, because none of the positive numbers 2k-150350024033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150350023993 and 150350024011.

It is not an unprimeable number, because it can be changed into a prime (150350020033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6834091991 + ... + 6834092012.

It is an arithmetic number, because the mean of its divisors is an integer number (41004552012).

Almost surely, 2150350024033 is an apocalyptic number.

It is an amenable number.

150350024033 is a deficient number, since it is larger than the sum of its proper divisors (13668184015).

150350024033 is a wasteful number, since it uses less digits than its factorization.

150350024033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13668184014.

The product of its (nonzero) digits is 5400, while the sum is 26.

Adding to 150350024033 its reverse (330420053051), we get a palindrome (480770077084).

The spelling of 150350024033 in words is "one hundred fifty billion, three hundred fifty million, twenty-four thousand, thirty-three".

Divisors: 1 11 13668184003 150350024033