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15040441231 is a prime number
BaseRepresentation
bin11100000000111101…
…01110101110001111
31102211012020120121221
432000132232232033
5221300323104411
610524240504211
71041500432614
oct160036565617
942735216557
1015040441231
116418a34122
122ab901b067
13155903868a
14a2975050b
155d0652071
hex3807aeb8f

15040441231 has 2 divisors, whose sum is σ = 15040441232. Its totient is φ = 15040441230.

The previous prime is 15040441219. The next prime is 15040441237. The reversal of 15040441231 is 13214404051.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 15040441231 - 219 = 15039916943 is a prime.

It is a super-2 number, since 2×150404412312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 15040441196 and 15040441205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15040441237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520220615 + 7520220616.

It is an arithmetic number, because the mean of its divisors is an integer number (7520220616).

Almost surely, 215040441231 is an apocalyptic number.

15040441231 is a deficient number, since it is larger than the sum of its proper divisors (1).

15040441231 is an equidigital number, since it uses as much as digits as its factorization.

15040441231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 15040441231 its reverse (13214404051), we get a palindrome (28254845282).

The spelling of 15040441231 in words is "fifteen billion, forty million, four hundred forty-one thousand, two hundred thirty-one".