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150410023 = 197916317
BaseRepresentation
bin10001111011100…
…01001100100111
3101111000121202121
420331301030213
5302001110043
622531450411
73504315121
oct1075611447
9344017677
10150410023
11779a2305
1242456a07
132521371a
1415d94211
15d310ded
hex8f71327

150410023 has 4 divisors (see below), whose sum is σ = 158326360. Its totient is φ = 142493688.

The previous prime is 150409997. The next prime is 150410059. The reversal of 150410023 is 320014051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150410023 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 150409979 and 150410006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (150410083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3958140 + ... + 3958177.

It is an arithmetic number, because the mean of its divisors is an integer number (39581590).

Almost surely, 2150410023 is an apocalyptic number.

150410023 is a deficient number, since it is larger than the sum of its proper divisors (7916337).

150410023 is an equidigital number, since it uses as much as digits as its factorization.

150410023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7916336.

The product of its (nonzero) digits is 120, while the sum is 16.

The square root of 150410023 is about 12264.1764093640. The cubic root of 150410023 is about 531.8129713133.

Adding to 150410023 its reverse (320014051), we get a palindrome (470424074).

The spelling of 150410023 in words is "one hundred fifty million, four hundred ten thousand, twenty-three".

Divisors: 1 19 7916317 150410023