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15041025053981 is a prime number
BaseRepresentation
bin1101101011100000001011…
…1101001001010100011101
31222020220111220020001110022
43122320002331021110131
53432413004403211411
651553430154521525
73111451423330013
oct332700275112435
958226456201408
1015041025053981
114879954584873
12182b074a362a5
13851493771b54
1439ddbd2728b3
151b13b912aedb
hexdae02f4951d

15041025053981 has 2 divisors, whose sum is σ = 15041025053982. Its totient is φ = 15041025053980.

The previous prime is 15041025053941. The next prime is 15041025054031. The reversal of 15041025053981 is 18935052014051.

15041025053981 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12355471051225 + 2685554002756 = 3515035^2 + 1638766^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15041025053981 is a prime.

It is a super-2 number, since 2×150410250539812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15041025053911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7520512526990 + 7520512526991.

It is an arithmetic number, because the mean of its divisors is an integer number (7520512526991).

Almost surely, 215041025053981 is an apocalyptic number.

It is an amenable number.

15041025053981 is a deficient number, since it is larger than the sum of its proper divisors (1).

15041025053981 is an equidigital number, since it uses as much as digits as its factorization.

15041025053981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216000, while the sum is 44.

The spelling of 15041025053981 in words is "fifteen trillion, forty-one billion, twenty-five million, fifty-three thousand, nine hundred eighty-one".