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15042547213 is a prime number
BaseRepresentation
bin11100000001001101…
…10000111000001101
31102211100012120111021
432000212300320031
5221301343002323
610524353554141
71041524353531
oct160046607015
942740176437
1015042547213
11641a142401
122ab9875951
1315595c5115
14a29b3bbc1
155d091b05d
hex3809b0e0d

15042547213 has 2 divisors, whose sum is σ = 15042547214. Its totient is φ = 15042547212.

The previous prime is 15042547207. The next prime is 15042547253. The reversal of 15042547213 is 31274524051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13740997284 + 1301549929 = 117222^2 + 36077^2 .

It is a cyclic number.

It is not a de Polignac number, because 15042547213 - 25 = 15042547181 is a prime.

It is a super-3 number, since 3×150425472133 (a number of 32 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15042547253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7521273606 + 7521273607.

It is an arithmetic number, because the mean of its divisors is an integer number (7521273607).

Almost surely, 215042547213 is an apocalyptic number.

It is an amenable number.

15042547213 is a deficient number, since it is larger than the sum of its proper divisors (1).

15042547213 is an equidigital number, since it uses as much as digits as its factorization.

15042547213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 33600, while the sum is 34.

The spelling of 15042547213 in words is "fifteen billion, forty-two million, five hundred forty-seven thousand, two hundred thirteen".