Search a number
-
+
15043122011 is a prime number
BaseRepresentation
bin11100000001010001…
…11101001101011011
31102211101021202222002
432000220331031123
5221302014401021
610524414151215
71041532266401
oct160050751533
942741252862
1015043122011
11641a4a5245
122ab9ab250b
131559766938
14a29c4b471
155d09d150b
hex380a3d35b

15043122011 has 2 divisors, whose sum is σ = 15043122012. Its totient is φ = 15043122010.

The previous prime is 15043121957. The next prime is 15043122019. The reversal of 15043122011 is 11022134051.

15043122011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11022134051) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15043122011 is a prime.

It is not a weakly prime, because it can be changed into another prime (15043122019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7521561005 + 7521561006.

It is an arithmetic number, because the mean of its divisors is an integer number (7521561006).

Almost surely, 215043122011 is an apocalyptic number.

15043122011 is a deficient number, since it is larger than the sum of its proper divisors (1).

15043122011 is an equidigital number, since it uses as much as digits as its factorization.

15043122011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 15043122011 its reverse (11022134051), we get a palindrome (26065256062).

The spelling of 15043122011 in words is "fifteen billion, forty-three million, one hundred twenty-two thousand, eleven".