Base | Representation |
---|---|
bin | 1000110000011010000… |
… | …1100111001111011101 |
3 | 112101021221211222002001 |
4 | 2030012201213033131 |
5 | 4431041413031031 |
6 | 153035204202301 |
7 | 13603610131303 |
oct | 2140641471735 |
9 | 471257758061 |
10 | 150433330141 |
11 | 58886769536 |
12 | 251a3999391 |
13 | 11255290723 |
14 | 73d1150273 |
15 | 3da6b78861 |
hex | 23068673dd |
150433330141 has 2 divisors, whose sum is σ = 150433330142. Its totient is φ = 150433330140.
The previous prime is 150433330121. The next prime is 150433330153. The reversal of 150433330141 is 141033334051.
150433330141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 135538104025 + 14895226116 = 368155^2 + 122046^2 .
It is an emirp because it is prime and its reverse (141033334051) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 150433330141 - 213 = 150433321949 is a prime.
It is a super-2 number, since 2×1504333301412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150433330121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75216665070 + 75216665071.
It is an arithmetic number, because the mean of its divisors is an integer number (75216665071).
Almost surely, 2150433330141 is an apocalyptic number.
It is an amenable number.
150433330141 is a deficient number, since it is larger than the sum of its proper divisors (1).
150433330141 is an equidigital number, since it uses as much as digits as its factorization.
150433330141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 28.
Adding to 150433330141 its reverse (141033334051), we get a palindrome (291466664192).
The spelling of 150433330141 in words is "one hundred fifty billion, four hundred thirty-three million, three hundred thirty thousand, one hundred forty-one".
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