Base | Representation |
---|---|
bin | 1101101100000001110110… |
… | …0011011101100011100111 |
3 | 1222021202211122101220002222 |
4 | 3123000131203131203213 |
5 | 3433040011134144201 |
6 | 52001522551422555 |
7 | 3112221355544201 |
oct | 333003543354347 |
9 | 58252748356088 |
10 | 15050061240551 |
11 | 4882771241557 |
12 | 1830977084a5b |
13 | 8522a3881ccc |
14 | 3a05d93c7771 |
15 | 1b17475a491b |
hex | db01d8dd8e7 |
15050061240551 has 2 divisors, whose sum is σ = 15050061240552. Its totient is φ = 15050061240550.
The previous prime is 15050061240421. The next prime is 15050061240587. The reversal of 15050061240551 is 15504216005051.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 15050061240551 - 234 = 15032881371367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15050061240751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7525030620275 + 7525030620276.
It is an arithmetic number, because the mean of its divisors is an integer number (7525030620276).
Almost surely, 215050061240551 is an apocalyptic number.
15050061240551 is a deficient number, since it is larger than the sum of its proper divisors (1).
15050061240551 is an equidigital number, since it uses as much as digits as its factorization.
15050061240551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30000, while the sum is 35.
The spelling of 15050061240551 in words is "fifteen trillion, fifty billion, sixty-one million, two hundred forty thousand, five hundred fifty-one".
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