Search a number
-
+
1505131213513 is a prime number
BaseRepresentation
bin10101111001110000110…
…011111011001011001001
312022220000011220210101111
4111321300303323023021
5144130002042313023
63111240413250321
7213512361136504
oct25716063731311
95286004823344
101505131213513
11530360371014
122038554939a1
13abc194c7115
1452bc4d2613b
1529242abe00d
hex15e70cfb2c9

1505131213513 has 2 divisors, whose sum is σ = 1505131213514. Its totient is φ = 1505131213512.

The previous prime is 1505131213471. The next prime is 1505131213571. The reversal of 1505131213513 is 3153121315051.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1267857984064 + 237273229449 = 1125992^2 + 487107^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1505131213513 is a prime.

It is a super-2 number, since 2×15051312135132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1505131213613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 752565606756 + 752565606757.

It is an arithmetic number, because the mean of its divisors is an integer number (752565606757).

Almost surely, 21505131213513 is an apocalyptic number.

It is an amenable number.

1505131213513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1505131213513 is an equidigital number, since it uses as much as digits as its factorization.

1505131213513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6750, while the sum is 31.

Adding to 1505131213513 its reverse (3153121315051), we get a palindrome (4658252528564).

The spelling of 1505131213513 in words is "one trillion, five hundred five billion, one hundred thirty-one million, two hundred thirteen thousand, five hundred thirteen".