Base | Representation |
---|---|
bin | 1000110000101110110… |
… | …0101100100001010111 |
3 | 112101112000011102100021 |
4 | 2030023230230201113 |
5 | 4431231122341211 |
6 | 153051544330011 |
7 | 13606012631161 |
oct | 2141354544127 |
9 | 471460142307 |
10 | 150520121431 |
11 | 58920759079 |
12 | 25208a73907 |
13 | 1126a25b014 |
14 | 73dc8a3931 |
15 | 3dae5be771 |
hex | 230bb2c857 |
150520121431 has 2 divisors, whose sum is σ = 150520121432. Its totient is φ = 150520121430.
The previous prime is 150520121419. The next prime is 150520121471. The reversal of 150520121431 is 134121025051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150520121431 - 229 = 149983250519 is a prime.
It is a super-2 number, since 2×1505201214312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 150520121396 and 150520121405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (150520121471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75260060715 + 75260060716.
It is an arithmetic number, because the mean of its divisors is an integer number (75260060716).
Almost surely, 2150520121431 is an apocalyptic number.
150520121431 is a deficient number, since it is larger than the sum of its proper divisors (1).
150520121431 is an equidigital number, since it uses as much as digits as its factorization.
150520121431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 150520121431 its reverse (134121025051), we get a palindrome (284641146482).
The spelling of 150520121431 in words is "one hundred fifty billion, five hundred twenty million, one hundred twenty-one thousand, four hundred thirty-one".
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