Base | Representation |
---|---|
bin | 1000110000110001001… |
… | …1111101010111010011 |
3 | 112101112201112100010211 |
4 | 2030030103331113103 |
5 | 4431241241222120 |
6 | 153052553104551 |
7 | 13606166256601 |
oct | 2141423752723 |
9 | 471481470124 |
10 | 150530414035 |
11 | 58926549061 |
12 | 252103b8157 |
13 | 1126c422b11 |
14 | 73dddc2871 |
15 | 3db045425a |
hex | 230c4fd5d3 |
150530414035 has 4 divisors (see below), whose sum is σ = 180636496848. Its totient is φ = 120424331224.
The previous prime is 150530413981. The next prime is 150530414081. The reversal of 150530414035 is 530414035051.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 150530414035 - 213 = 150530405843 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 150530413988 and 150530414006.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15053041399 + ... + 15053041408.
It is an arithmetic number, because the mean of its divisors is an integer number (45159124212).
Almost surely, 2150530414035 is an apocalyptic number.
150530414035 is a deficient number, since it is larger than the sum of its proper divisors (30106082813).
150530414035 is an equidigital number, since it uses as much as digits as its factorization.
150530414035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30106082812.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 150530414035 its reverse (530414035051), we get a palindrome (680944449086).
The spelling of 150530414035 in words is "one hundred fifty billion, five hundred thirty million, four hundred fourteen thousand, thirty-five".
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