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15053214311 = 15199690161
BaseRepresentation
bin11100000010011110…
…11101001001100111
31102212002021111222222
432001033131021213
5221312110324221
610525414342555
71042014132122
oct160117351147
942762244888
1015053214311
116425168793
122b0135aa5b
13155b88b505
14a2b3173b9
155d18269ab
hex3813dd267

15053214311 has 4 divisors (see below), whose sum is σ = 15152904624. Its totient is φ = 14953524000.

The previous prime is 15053214277. The next prime is 15053214361. The reversal of 15053214311 is 11341235051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15053214311 is a prime.

It is a super-2 number, since 2×150532143112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15053214361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49844930 + ... + 49845231.

It is an arithmetic number, because the mean of its divisors is an integer number (3788226156).

Almost surely, 215053214311 is an apocalyptic number.

15053214311 is a deficient number, since it is larger than the sum of its proper divisors (99690313).

15053214311 is an equidigital number, since it uses as much as digits as its factorization.

15053214311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 99690312.

The product of its (nonzero) digits is 1800, while the sum is 26.

Adding to 15053214311 its reverse (11341235051), we get a palindrome (26394449362).

The spelling of 15053214311 in words is "fifteen billion, fifty-three million, two hundred fourteen thousand, three hundred eleven".

Divisors: 1 151 99690161 15053214311