Base | Representation |
---|---|
bin | 100010001110100011001010… |
… | …100101000011001010100011 |
3 | 201201222212001100012101011221 |
4 | 202032203022211003022203 |
5 | 124212314412100001011 |
6 | 1252054032305115511 |
7 | 43464452202200623 |
oct | 4216431245031243 |
9 | 651885040171157 |
10 | 150533412500131 |
11 | 43a67952a5a631 |
12 | 14a72473328b97 |
13 | 65cc31706040b |
14 | 2925bdad8a883 |
15 | 1260abd562971 |
hex | 88e8ca9432a3 |
150533412500131 has 2 divisors, whose sum is σ = 150533412500132. Its totient is φ = 150533412500130.
The previous prime is 150533412500087. The next prime is 150533412500209. The reversal of 150533412500131 is 131005214335051.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150533412500131 - 223 = 150533404111523 is a prime.
It is a super-2 number, since 2×1505334125001312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (150533412507131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75266706250065 + 75266706250066.
It is an arithmetic number, because the mean of its divisors is an integer number (75266706250066).
Almost surely, 2150533412500131 is an apocalyptic number.
150533412500131 is a deficient number, since it is larger than the sum of its proper divisors (1).
150533412500131 is an equidigital number, since it uses as much as digits as its factorization.
150533412500131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 150533412500131 its reverse (131005214335051), we get a palindrome (281538626835182).
The spelling of 150533412500131 in words is "one hundred fifty trillion, five hundred thirty-three billion, four hundred twelve million, five hundred thousand, one hundred thirty-one".
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