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150533412507131 is a prime number
BaseRepresentation
bin100010001110100011001010…
…100101000100110111111011
3201201222212001100012201210012
4202032203022211010313323
5124212314412100212011
61252054032305212135
743464452202230213
oct4216431245046773
9651885040181705
10150533412507131
1143a67952a64915
1214a7247333104b
1365cc317063664
142925bdad8d243
151260abd564a8b
hex88e8ca944dfb

150533412507131 has 2 divisors, whose sum is σ = 150533412507132. Its totient is φ = 150533412507130.

The previous prime is 150533412507091. The next prime is 150533412507167. The reversal of 150533412507131 is 131705214335051.

150533412507131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-150533412507131 is a prime.

It is a super-2 number, since 2×1505334125071312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (150533412500131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75266706253565 + 75266706253566.

It is an arithmetic number, because the mean of its divisors is an integer number (75266706253566).

Almost surely, 2150533412507131 is an apocalyptic number.

150533412507131 is a deficient number, since it is larger than the sum of its proper divisors (1).

150533412507131 is an equidigital number, since it uses as much as digits as its factorization.

150533412507131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 189000, while the sum is 41.

The spelling of 150533412507131 in words is "one hundred fifty trillion, five hundred thirty-three billion, four hundred twelve million, five hundred seven thousand, one hundred thirty-one".