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15055523145739 is a prime number
BaseRepresentation
bin1101101100010110001100…
…0110111110100000001011
31222022021221021221102110201
43123011203012332200023
53433132202411130424
652004224543153031
73112503620144056
oct333054306764013
958267837842421
1015055523145739
11488501435678a
121831a402a5777
1385296431837b
143a0996965a9d
151b1966d4bd44
hexdb1631be80b

15055523145739 has 2 divisors, whose sum is σ = 15055523145740. Its totient is φ = 15055523145738.

The previous prime is 15055523145737. The next prime is 15055523145743. The reversal of 15055523145739 is 93754132555051.

15055523145739 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15055523145739 - 21 = 15055523145737 is a prime.

It is a super-2 number, since 2×150555231457392 (a number of 27 digits) contains 22 as substring.

Together with 15055523145737, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 15055523145739.

It is not a weakly prime, because it can be changed into another prime (15055523145737) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7527761572869 + 7527761572870.

It is an arithmetic number, because the mean of its divisors is an integer number (7527761572870).

Almost surely, 215055523145739 is an apocalyptic number.

15055523145739 is a deficient number, since it is larger than the sum of its proper divisors (1).

15055523145739 is an equidigital number, since it uses as much as digits as its factorization.

15055523145739 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14175000, while the sum is 55.

The spelling of 15055523145739 in words is "fifteen trillion, fifty-five billion, five hundred twenty-three million, one hundred forty-five thousand, seven hundred thirty-nine".