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15068132353 = 116819128987
BaseRepresentation
bin11100000100010000…
…10111010000000001
31102220010100102201001
432002020113100001
5221324420213403
610531110212001
71042255004011
oct160210272001
942803312631
1015068132353
11643262794a
122b06354001
1315619b2761
14a2d2bbc41
155d2cc1c1d
hex382217401

15068132353 has 4 divisors (see below), whose sum is σ = 15068378160. Its totient is φ = 15067886548.

The previous prime is 15068132351. The next prime is 15068132357. The reversal of 15068132353 is 35323186051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 15068132353 - 21 = 15068132351 is a prime.

It is a super-2 number, since 2×150681323532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15068132351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 52326 + ... + 181312.

It is an arithmetic number, because the mean of its divisors is an integer number (3767094540).

Almost surely, 215068132353 is an apocalyptic number.

It is an amenable number.

15068132353 is a deficient number, since it is larger than the sum of its proper divisors (245807).

15068132353 is a wasteful number, since it uses less digits than its factorization.

15068132353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 245806.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 15068132353 in words is "fifteen billion, sixty-eight million, one hundred thirty-two thousand, three hundred fifty-three".

Divisors: 1 116819 128987 15068132353