Base | Representation |
---|---|
bin | 1000110001011101011… |
… | …0000000010111100001 |
3 | 112102000121210200100121 |
4 | 2030113112000113201 |
5 | 4432131132000001 |
6 | 153123204120241 |
7 | 13613604420043 |
oct | 2142726002741 |
9 | 472017720317 |
10 | 150715500001 |
11 | 58a10a74970 |
12 | 25262396081 |
13 | 1129b887941 |
14 | 741a801a93 |
15 | 3dc18146a1 |
hex | 23175805e1 |
150715500001 has 4 divisors (see below), whose sum is σ = 164416909104. Its totient is φ = 137014090900.
The previous prime is 150715499993. The next prime is 150715500017. The reversal of 150715500001 is 100005517051.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 150715500001 - 23 = 150715499993 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (150715500071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6850704535 + ... + 6850704556.
It is an arithmetic number, because the mean of its divisors is an integer number (41104227276).
Almost surely, 2150715500001 is an apocalyptic number.
150715500001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
150715500001 is a deficient number, since it is larger than the sum of its proper divisors (13701409103).
150715500001 is a wasteful number, since it uses less digits than its factorization.
150715500001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13701409102.
The product of its (nonzero) digits is 875, while the sum is 25.
The spelling of 150715500001 in words is "one hundred fifty billion, seven hundred fifteen million, five hundred thousand, one".
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