150837000131 has 2 divisors, whose sum is σ = 150837000132. Its totient is φ = 150837000130.

The previous prime is 150837000109. The next prime is 150837000133. The reversal of 150837000131 is 131000738051.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 150837000131 - 2¹⁰ = 150836999107 is a prime.

It is a super-2 number, since 2×150837000131² (a number of 23 digits) contains 22 as substring.

Together with 150837000133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 150837000094 and 150837000103.

It is not a weakly prime, because it can be changed into another prime (150837000133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75418500065 + 75418500066.

It is an arithmetic number, because the mean of its divisors is an integer number (75418500066).

Almost surely, 2^150837000131 is an apocalyptic number.

150837000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

150837000131 is an equidigital number, since it uses as much as digits as its factorization.

150837000131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2520, while the sum is 29.

Adding to 150837000131 its reverse (131000738051), we get a palindrome (281837738182).

The spelling of 150837000131 in words is "one hundred fifty billion, eight hundred thirty-seven million, one hundred thirty-one", and thus it is an aban number.