Base | Representation |
---|---|
bin | 1000110010011000001… |
… | …0111001001100100011 |
3 | 112102122210220200222112 |
4 | 2030212002321030203 |
5 | 4433132302220011 |
6 | 153203454425535 |
7 | 13622661041564 |
oct | 2144602711443 |
9 | 472583820875 |
10 | 150962148131 |
11 | 590282192a3 |
12 | 25310b022ab |
13 | 1130a9c5792 |
14 | 744148816b |
15 | 3dd82d558b |
hex | 23260b9323 |
150962148131 has 2 divisors, whose sum is σ = 150962148132. Its totient is φ = 150962148130.
The previous prime is 150962148121. The next prime is 150962148151. The reversal of 150962148131 is 131841269051.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 150962148131 - 26 = 150962148067 is a prime.
It is a super-2 number, since 2×1509621481312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (150962148121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75481074065 + 75481074066.
It is an arithmetic number, because the mean of its divisors is an integer number (75481074066).
Almost surely, 2150962148131 is an apocalyptic number.
150962148131 is a deficient number, since it is larger than the sum of its proper divisors (1).
150962148131 is an equidigital number, since it uses as much as digits as its factorization.
150962148131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 150962148131 in words is "one hundred fifty billion, nine hundred sixty-two million, one hundred forty-eight thousand, one hundred thirty-one".
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