151020402314 has 4 divisors (see below), whose sum is σ = 226530603474. Its totient is φ = 75510201156.

The previous prime is 151020402307. The next prime is 151020402331. The reversal of 151020402314 is 413204020151.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 149937005089 + 1083397225 = 387217^2 + 32915^2 .

It is a super-3 number, since 3×151020402314³ (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 151020402314.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37755100577 + ... + 37755100580.

Almost surely, 2^151020402314 is an apocalyptic number.

151020402314 is a deficient number, since it is larger than the sum of its proper divisors (75510201160).

151020402314 is an equidigital number, since it uses as much as digits as its factorization.

151020402314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 75510201159.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 151020402314 its reverse (413204020151), we get a palindrome (564224422465).

The spelling of 151020402314 in words is "one hundred fifty-one billion, twenty million, four hundred two thousand, three hundred fourteen".