Base | Representation |
---|---|
bin | 1000110010101010110… |
… | …0010001101111010111 |
3 | 112102212020121100021221 |
4 | 2030222230101233113 |
5 | 4433312231333211 |
6 | 153215321351211 |
7 | 13624625466415 |
oct | 2145254215727 |
9 | 472766540257 |
10 | 151040105431 |
11 | 59068224816 |
12 | 25333038507 |
13 | 11320bbc167 |
14 | 744b97c2b5 |
15 | 3de0083c71 |
hex | 232ab11bd7 |
151040105431 has 2 divisors, whose sum is σ = 151040105432. Its totient is φ = 151040105430.
The previous prime is 151040105371. The next prime is 151040105519. The reversal of 151040105431 is 134501040151.
It is a weak prime.
It is an emirp because it is prime and its reverse (134501040151) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 151040105431 - 217 = 151039974359 is a prime.
It is a super-3 number, since 3×1510401054313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 151040105396 and 151040105405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151040105131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75520052715 + 75520052716.
It is an arithmetic number, because the mean of its divisors is an integer number (75520052716).
Almost surely, 2151040105431 is an apocalyptic number.
151040105431 is a deficient number, since it is larger than the sum of its proper divisors (1).
151040105431 is an equidigital number, since it uses as much as digits as its factorization.
151040105431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 151040105431 its reverse (134501040151), we get a palindrome (285541145582).
The spelling of 151040105431 in words is "one hundred fifty-one billion, forty million, one hundred five thousand, four hundred thirty-one".
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