Base | Representation |
---|---|
bin | 1000110010101100000… |
… | …0101101010000100111 |
3 | 112102212121200102210111 |
4 | 2030223000231100213 |
5 | 4433320114223111 |
6 | 153220032233451 |
7 | 13625022143413 |
oct | 2145300552047 |
9 | 472777612714 |
10 | 151045461031 |
11 | 59070252533 |
12 | 2533499b887 |
13 | 11322045a5a |
14 | 744c573d43 |
15 | 3de0790a21 |
hex | 232b02d427 |
151045461031 has 2 divisors, whose sum is σ = 151045461032. Its totient is φ = 151045461030.
The previous prime is 151045460971. The next prime is 151045461041. The reversal of 151045461031 is 130164540151.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 151045461031 - 27 = 151045460903 is a prime.
It is a super-2 number, since 2×1510454610312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 151045460984 and 151045461002.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151045461041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75522730515 + 75522730516.
It is an arithmetic number, because the mean of its divisors is an integer number (75522730516).
Almost surely, 2151045461031 is an apocalyptic number.
151045461031 is a deficient number, since it is larger than the sum of its proper divisors (1).
151045461031 is an equidigital number, since it uses as much as digits as its factorization.
151045461031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 31.
The spelling of 151045461031 in words is "one hundred fifty-one billion, forty-five million, four hundred sixty-one thousand, thirty-one".
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