151124303540013 has 4 divisors (see below), whose sum is σ = 201499071386688. Its totient is φ = 100749535693340.

The previous prime is 151124303539991. The next prime is 151124303540033. The reversal of 151124303540013 is 310045303421151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 151124303540013 - 2⁹ = 151124303539501 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151124303540033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25187383923333 + ... + 25187383923338.

It is an arithmetic number, because the mean of its divisors is an integer number (50374767846672).

Almost surely, 2^{151124303540013} is an apocalyptic number.

It is an amenable number.

151124303540013 is a deficient number, since it is larger than the sum of its proper divisors (50374767846675).

151124303540013 is an equidigital number, since it uses as much as digits as its factorization.

151124303540013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50374767846674.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 151124303540013 its reverse (310045303421151), we get a palindrome (461169606961164).

The spelling of 151124303540013 in words is "one hundred fifty-one trillion, one hundred twenty-four billion, three hundred three million, five hundred forty thousand, thirteen".