151131021401 has 2 divisors, whose sum is σ = 151131021402. Its totient is φ = 151131021400.

The previous prime is 151131021383. The next prime is 151131021407. The reversal of 151131021401 is 104120131151.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130954239376 + 20176782025 = 361876^2 + 142045^2 .

It is an emirp because it is prime and its reverse (104120131151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151131021401 - 2¹⁴ = 151131005017 is a prime.

It is not a weakly prime, because it can be changed into another prime (151131021407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75565510700 + 75565510701.

It is an arithmetic number, because the mean of its divisors is an integer number (75565510701).

Almost surely, 2^151131021401 is an apocalyptic number.

It is an amenable number.

151131021401 is a deficient number, since it is larger than the sum of its proper divisors (1).

151131021401 is an equidigital number, since it uses as much as digits as its factorization.

151131021401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 151131021401 its reverse (104120131151), we get a palindrome (255251152552).

The spelling of 151131021401 in words is "one hundred fifty-one billion, one hundred thirty-one million, twenty-one thousand, four hundred one".