Base | Representation |
---|---|
bin | 1000110011000000011… |
… | …1000110000001011111 |
3 | 112110002120200100120022 |
4 | 2030300013012001133 |
5 | 4434004020141112 |
6 | 153232330142355 |
7 | 13630111325522 |
oct | 2146007060137 |
9 | 473076610508 |
10 | 151131021407 |
11 | 59104581293 |
12 | 253595819bb |
13 | 113369a1cb2 |
14 | 7459a86bb9 |
15 | 3de8041d72 |
hex | 23301c605f |
151131021407 has 2 divisors, whose sum is σ = 151131021408. Its totient is φ = 151131021406.
The previous prime is 151131021401. The next prime is 151131021451. The reversal of 151131021407 is 704120131151.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 151131021407 - 226 = 151063912543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151131021401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75565510703 + 75565510704.
It is an arithmetic number, because the mean of its divisors is an integer number (75565510704).
Almost surely, 2151131021407 is an apocalyptic number.
151131021407 is a deficient number, since it is larger than the sum of its proper divisors (1).
151131021407 is an equidigital number, since it uses as much as digits as its factorization.
151131021407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 840, while the sum is 26.
Adding to 151131021407 its reverse (704120131151), we get a palindrome (855251152558).
The spelling of 151131021407 in words is "one hundred fifty-one billion, one hundred thirty-one million, twenty-one thousand, four hundred seven".
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