15113144001 has 4 divisors (see below), whose sum is σ = 20150858672. Its totient is φ = 10075429332.

The previous prime is 15113143957. The next prime is 15113144047. The reversal of 15113144001 is 10044131151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 15113144001 - 2⁷ = 15113143873 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (15113144401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2518857331 + ... + 2518857336.

It is an arithmetic number, because the mean of its divisors is an integer number (5037714668).

Almost surely, 2^15113144001 is an apocalyptic number.

It is an amenable number.

15113144001 is a deficient number, since it is larger than the sum of its proper divisors (5037714671).

15113144001 is an equidigital number, since it uses as much as digits as its factorization.

15113144001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5037714670.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 15113144001 its reverse (10044131151), we get a palindrome (25157275152).

The spelling of 15113144001 in words is "fifteen billion, one hundred thirteen million, one hundred forty-four thousand, one".