151134433 has 2 divisors, whose sum is σ = 151134434. Its totient is φ = 151134432.

The previous prime is 151134409. The next prime is 151134461. The reversal of 151134433 is 334431151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98962704 + 52171729 = 9948^2 + 7223^2 .

It is an emirp because it is prime and its reverse (334431151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151134433 - 2⁹ = 151133921 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151134398 and 151134407.

It is not a weakly prime, because it can be changed into another prime (151134133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75567216 + 75567217.

It is an arithmetic number, because the mean of its divisors is an integer number (75567217).

Almost surely, 2^151134433 is an apocalyptic number.

It is an amenable number.

151134433 is a deficient number, since it is larger than the sum of its proper divisors (1).

151134433 is an equidigital number, since it uses as much as digits as its factorization.

151134433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2160, while the sum is 25.

The square root of 151134433 is about 12293.6745117154. The cubic root of 151134433 is about 532.6653830312.

Adding to 151134433 its reverse (334431151), we get a palindrome (485565584).

The spelling of 151134433 in words is "one hundred fifty-one million, one hundred thirty-four thousand, four hundred thirty-three".