Base | Representation |
---|---|
bin | 11100001001101101… |
… | …10101110010010011 |
3 | 1110000022102011121212 |
4 | 32010312311302103 |
5 | 221423122323413 |
6 | 10535422410335 |
7 | 1043351531225 |
oct | 160466656223 |
9 | 43008364555 |
10 | 15113870483 |
11 | 6456427658 |
12 | 2b197309ab |
13 | 156b30803a |
14 | a353c6415 |
15 | 5d6d08ca8 |
hex | 384db5c93 |
15113870483 has 2 divisors, whose sum is σ = 15113870484. Its totient is φ = 15113870482.
The previous prime is 15113870477. The next prime is 15113870533. The reversal of 15113870483 is 38407831151.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15113870483 - 26 = 15113870419 is a prime.
It is a super-3 number, since 3×151138704833 (a number of 32 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 15113870483.
It is not a weakly prime, because it can be changed into another prime (15113870413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7556935241 + 7556935242.
It is an arithmetic number, because the mean of its divisors is an integer number (7556935242).
Almost surely, 215113870483 is an apocalyptic number.
15113870483 is a deficient number, since it is larger than the sum of its proper divisors (1).
15113870483 is an equidigital number, since it uses as much as digits as its factorization.
15113870483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 41.
The spelling of 15113870483 in words is "fifteen billion, one hundred thirteen million, eight hundred seventy thousand, four hundred eighty-three".
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