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151142001 = 350380667
BaseRepresentation
bin10010000001000…
…11111001110001
3101112101210211220
421000203321301
5302143021001
622555255253
73513454143
oct1100437161
9345353756
10151142001
117835224a
124274a529
132540b94a
1416104c93
15d407c36
hex9023e71

151142001 has 4 divisors (see below), whose sum is σ = 201522672. Its totient is φ = 100761332.

The previous prime is 151141973. The next prime is 151142023. The reversal of 151142001 is 100241151.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100241151 = 333413717.

It is a cyclic number.

It is not a de Polignac number, because 151142001 - 26 = 151141937 is a prime.

It is not an unprimeable number, because it can be changed into a prime (151142071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25190331 + ... + 25190336.

It is an arithmetic number, because the mean of its divisors is an integer number (50380668).

Almost surely, 2151142001 is an apocalyptic number.

It is an amenable number.

151142001 is a deficient number, since it is larger than the sum of its proper divisors (50380671).

151142001 is an equidigital number, since it uses as much as digits as its factorization.

151142001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50380670.

The product of its (nonzero) digits is 40, while the sum is 15.

The square root of 151142001 is about 12293.9823084304. The cubic root of 151142001 is about 532.6742738891.

Adding to 151142001 its reverse (100241151), we get a palindrome (251383152).

The spelling of 151142001 in words is "one hundred fifty-one million, one hundred forty-two thousand, one".

Divisors: 1 3 50380667 151142001