Base | Representation |
---|---|
bin | 1000110011000011001… |
… | …0100111110100100011 |
3 | 112110010101011002000011 |
4 | 2030300302213310203 |
5 | 4434014430311120 |
6 | 153233414505351 |
7 | 13630310321620 |
oct | 2146062476443 |
9 | 473111132004 |
10 | 151142432035 |
11 | 5910aa65261 |
12 | 25361365257 |
13 | 1133916894a |
14 | 745b3b7347 |
15 | 3de9047c5a |
hex | 2330ca7d23 |
151142432035 has 8 divisors (see below), whose sum is σ = 207281049696. Its totient is φ = 103640524800.
The previous prime is 151142432027. The next prime is 151142432071. The reversal of 151142432035 is 530234241151.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 151142432035 - 23 = 151142432027 is a prime.
It is a super-2 number, since 2×1511424320352 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 151142431988 and 151142432006.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2159177566 + ... + 2159177635.
It is an arithmetic number, because the mean of its divisors is an integer number (25910131212).
Almost surely, 2151142432035 is an apocalyptic number.
151142432035 is a deficient number, since it is larger than the sum of its proper divisors (56138617661).
151142432035 is an equidigital number, since it uses as much as digits as its factorization.
151142432035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4318355213.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 151142432035 its reverse (530234241151), we get a palindrome (681376673186).
The spelling of 151142432035 in words is "one hundred fifty-one billion, one hundred forty-two million, four hundred thirty-two thousand, thirty-five".
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