15114352423 has 4 divisors (see below), whose sum is σ = 15233363200. Its totient is φ = 14995341648.

The previous prime is 15114352387. The next prime is 15114352459. The reversal of 15114352423 is 32425341151.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 32425341151 = 7 ⋅4632191593.

It is an interprime number because it is at equal distance from previous prime (15114352387) and next prime (15114352459).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15114352423 is a prime.

It is a super-3 number, since 3×15114352423³ (a number of 32 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15114352493) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59505198 + ... + 59505451.

It is an arithmetic number, because the mean of its divisors is an integer number (3808340800).

Almost surely, 2^15114352423 is an apocalyptic number.

15114352423 is a deficient number, since it is larger than the sum of its proper divisors (119010777).

15114352423 is a wasteful number, since it uses less digits than its factorization.

15114352423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 119010776.

The product of its digits is 14400, while the sum is 31.

Adding to 15114352423 its reverse (32425341151), we get a palindrome (47539693574).

The spelling of 15114352423 in words is "fifteen billion, one hundred fourteen million, three hundred fifty-two thousand, four hundred twenty-three".