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151144045413 = 350381348471
BaseRepresentation
bin1000110011000011100…
…0110001101101100101
3112110010111012001010220
42030300320301231211
54434020333423123
6153233513234553
713630330121424
oct2146070615545
9473114161126
10151144045413
1159110967429
1225361a02a59
13113395b20ca
14745b6b72bb
153de9265ce3
hex2330e31b65

151144045413 has 4 divisors (see below), whose sum is σ = 201525393888. Its totient is φ = 100762696940.

The previous prime is 151144045337. The next prime is 151144045447. The reversal of 151144045413 is 314540441151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 151144045413 - 29 = 151144044901 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (151144045463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25190674233 + ... + 25190674238.

It is an arithmetic number, because the mean of its divisors is an integer number (50381348472).

Almost surely, 2151144045413 is an apocalyptic number.

It is an amenable number.

151144045413 is a deficient number, since it is larger than the sum of its proper divisors (50381348475).

151144045413 is an equidigital number, since it uses as much as digits as its factorization.

151144045413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50381348474.

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 151144045413 its reverse (314540441151), we get a palindrome (465684486564).

The spelling of 151144045413 in words is "one hundred fifty-one billion, one hundred forty-four million, forty-five thousand, four hundred thirteen".

Divisors: 1 3 50381348471 151144045413