Base | Representation |
---|---|
bin | 1101101111110010010001… |
… | …1111011100001101010011 |
3 | 1222111221102121111002221001 |
4 | 3123330210133130031103 |
5 | 3440114201121331103 |
6 | 52051315151042431 |
7 | 3116664634241260 |
oct | 333744437341523 |
9 | 58457377432831 |
10 | 15114602136403 |
11 | 48a8080961900 |
12 | 1841389810417 |
13 | 8583bb004203 |
14 | 3a379cd90267 |
15 | 1b32737c301d |
hex | dbf247dc353 |
15114602136403 has 48 divisors (see below), whose sum is σ = 19192431863808. Its totient is φ = 11650357224000.
The previous prime is 15114602136371. The next prime is 15114602136437. The reversal of 15114602136403 is 30463120641151.
It is not a de Polignac number, because 15114602136403 - 25 = 15114602136371 is a prime.
It is a Smith number, since the sum of its digits (37) coincides with the sum of the digits of its prime factors.
It is not an unprimeable number, because it can be changed into a prime (15114602136203) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 94278250 + ... + 94438432.
It is an arithmetic number, because the mean of its divisors is an integer number (399842330496).
Almost surely, 215114602136403 is an apocalyptic number.
15114602136403 is a deficient number, since it is larger than the sum of its proper divisors (4077829727405).
15114602136403 is a wasteful number, since it uses less digits than its factorization.
15114602136403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 161416 (or 161405 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 37.
Adding to 15114602136403 its reverse (30463120641151), we get a palindrome (45577722777554).
The spelling of 15114602136403 in words is "fifteen trillion, one hundred fourteen billion, six hundred two million, one hundred thirty-six thousand, four hundred three".
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