Base | Representation |
---|---|
bin | 11100001001110100… |
… | …01010011001111011 |
3 | 1110000101001102020222 |
4 | 32010322022121323 |
5 | 221423333210441 |
6 | 10535453210255 |
7 | 1043362116242 |
oct | 160472123173 |
9 | 43011042228 |
10 | 15114741371 |
11 | 64569719a4 |
12 | 2b19a9098b |
13 | 156b551562 |
14 | a35571959 |
15 | 5d6e2bd4b |
hex | 384e8a67b |
15114741371 has 2 divisors, whose sum is σ = 15114741372. Its totient is φ = 15114741370.
The previous prime is 15114741221. The next prime is 15114741373. The reversal of 15114741371 is 17314741151.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15114741371 is a prime.
Together with 15114741373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (15114741373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7557370685 + 7557370686.
It is an arithmetic number, because the mean of its divisors is an integer number (7557370686).
Almost surely, 215114741371 is an apocalyptic number.
15114741371 is a deficient number, since it is larger than the sum of its proper divisors (1).
15114741371 is an equidigital number, since it uses as much as digits as its factorization.
15114741371 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11760, while the sum is 35.
The spelling of 15114741371 in words is "fifteen billion, one hundred fourteen million, seven hundred forty-one thousand, three hundred seventy-one".
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