Base | Representation |
---|---|
bin | 1000110011010001101… |
… | …1010010010011000111 |
3 | 112110021121220202110202 |
4 | 2030310123102103013 |
5 | 4434131034022211 |
6 | 153243434041115 |
7 | 13631650615244 |
oct | 2146433222307 |
9 | 473247822422 |
10 | 151203423431 |
11 | 59141432a75 |
12 | 2537987919b |
13 | 113489a1c28 |
14 | 74655325cb |
15 | 3dee59453b |
hex | 23346d24c7 |
151203423431 has 2 divisors, whose sum is σ = 151203423432. Its totient is φ = 151203423430.
The previous prime is 151203423403. The next prime is 151203423487. The reversal of 151203423431 is 134324302151.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-151203423431 is a prime.
It is a super-2 number, since 2×1512034234312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 151203423394 and 151203423403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151203423491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75601711715 + 75601711716.
It is an arithmetic number, because the mean of its divisors is an integer number (75601711716).
Almost surely, 2151203423431 is an apocalyptic number.
151203423431 is a deficient number, since it is larger than the sum of its proper divisors (1).
151203423431 is an equidigital number, since it uses as much as digits as its factorization.
151203423431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 151203423431 its reverse (134324302151), we get a palindrome (285527725582).
The spelling of 151203423431 in words is "one hundred fifty-one billion, two hundred three million, four hundred twenty-three thousand, four hundred thirty-one".
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