Base | Representation |
---|---|
bin | 1101110000000111111001… |
… | …0001101100100011000101 |
3 | 1222112111101220200101011120 |
4 | 3130001332101230203011 |
5 | 3440213041240400203 |
6 | 52054114545224153 |
7 | 3120261456503166 |
oct | 334017621544305 |
9 | 58474356611146 |
10 | 15120403450053 |
11 | 48aa5886176a0 |
12 | 1842528632059 |
13 | 858b03b85895 |
14 | 3a3b8d63d76d |
15 | 1b34b2c60b53 |
hex | dc07e46c8c5 |
15120403450053 has 32 divisors (see below), whose sum is σ = 22029406185600. Its totient is φ = 9148844851200.
The previous prime is 15120403450039. The next prime is 15120403450109. The reversal of 15120403450053 is 35005430402151.
It is not a de Polignac number, because 15120403450053 - 28 = 15120403449797 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 15120403449996 and 15120403450023.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15120403452053) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 379232203 + ... + 379272071.
It is an arithmetic number, because the mean of its divisors is an integer number (688418943300).
Almost surely, 215120403450053 is an apocalyptic number.
It is an amenable number.
15120403450053 is a deficient number, since it is larger than the sum of its proper divisors (6909002735547).
15120403450053 is a wasteful number, since it uses less digits than its factorization.
15120403450053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58453.
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 15120403450053 in words is "fifteen trillion, one hundred twenty billion, four hundred three million, four hundred fifty thousand, fifty-three".
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