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151205113 is a prime number
BaseRepresentation
bin10010000001100…
…11010011111001
3101112112000102101
421000303103321
5302202030423
623000503401
73514136143
oct1100632371
9345460371
10151205113
1178395704
124277ab61
13254315a7
141611dc93
15d41b7ad
hex90334f9

151205113 has 2 divisors, whose sum is σ = 151205114. Its totient is φ = 151205112.

The previous prime is 151205107. The next prime is 151205137. The reversal of 151205113 is 311502151.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131606784 + 19598329 = 11472^2 + 4427^2 .

It is an emirp because it is prime and its reverse (311502151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151205113 - 25 = 151205081 is a prime.

It is not a weakly prime, because it can be changed into another prime (151205143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75602556 + 75602557.

It is an arithmetic number, because the mean of its divisors is an integer number (75602557).

Almost surely, 2151205113 is an apocalyptic number.

It is an amenable number.

151205113 is a deficient number, since it is larger than the sum of its proper divisors (1).

151205113 is an equidigital number, since it uses as much as digits as its factorization.

151205113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150, while the sum is 19.

The square root of 151205113 is about 12296.5488247719. The cubic root of 151205113 is about 532.7484060746.

Adding to 151205113 its reverse (311502151), we get a palindrome (462707264).

It can be divided in two parts, 15 and 1205113, that added together give a triangular number (1205128 = T1552).

The spelling of 151205113 in words is "one hundred fifty-one million, two hundred five thousand, one hundred thirteen".