Base | Representation |
---|---|
bin | 1000110011011100010… |
… | …1110011111000000111 |
3 | 112110101202000212002222 |
4 | 2030313011303320013 |
5 | 4434224010003242 |
6 | 153252112122555 |
7 | 13633032565646 |
oct | 2146705637007 |
9 | 473352025088 |
10 | 151248125447 |
11 | 59164695291 |
12 | 2539083645b |
13 | 11355023a23 |
14 | 746b44b35d |
15 | 3e034745d2 |
hex | 2337173e07 |
151248125447 has 2 divisors, whose sum is σ = 151248125448. Its totient is φ = 151248125446.
The previous prime is 151248125389. The next prime is 151248125453. The reversal of 151248125447 is 744521842151.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 151248125447 - 26 = 151248125383 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 151248125398 and 151248125407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (151248125467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75624062723 + 75624062724.
It is an arithmetic number, because the mean of its divisors is an integer number (75624062724).
Almost surely, 2151248125447 is an apocalyptic number.
151248125447 is a deficient number, since it is larger than the sum of its proper divisors (1).
151248125447 is an equidigital number, since it uses as much as digits as its factorization.
151248125447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 358400, while the sum is 44.
Adding to 151248125447 its reverse (744521842151), we get a palindrome (895769967598).
The spelling of 151248125447 in words is "one hundred fifty-one billion, two hundred forty-eight million, one hundred twenty-five thousand, four hundred forty-seven".
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