Base | Representation |
---|---|
bin | 11100001011101011… |
… | …01011001100000011 |
3 | 1110001110102000111111 |
4 | 32011311223030003 |
5 | 221441331422042 |
6 | 10541211424151 |
7 | 1043641533454 |
oct | 160565531403 |
9 | 43043360444 |
10 | 15130342147 |
11 | 6464757aa8 |
12 | 2b23155057 |
13 | 157185449b |
14 | a3767312b |
15 | 5d84ae517 |
hex | 385d6b303 |
15130342147 has 2 divisors, whose sum is σ = 15130342148. Its totient is φ = 15130342146.
The previous prime is 15130342133. The next prime is 15130342151. The reversal of 15130342147 is 74124303151.
15130342147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15130342147 is a prime.
It is not a weakly prime, because it can be changed into another prime (15130342187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7565171073 + 7565171074.
It is an arithmetic number, because the mean of its divisors is an integer number (7565171074).
Almost surely, 215130342147 is an apocalyptic number.
15130342147 is a deficient number, since it is larger than the sum of its proper divisors (1).
15130342147 is an equidigital number, since it uses as much as digits as its factorization.
15130342147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 31.
Adding to 15130342147 its reverse (74124303151), we get a palindrome (89254645298).
The spelling of 15130342147 in words is "fifteen billion, one hundred thirty million, three hundred forty-two thousand, one hundred forty-seven".
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