1513110421 has 4 divisors (see below), whose sum is σ = 1513947744. Its totient is φ = 1512273100.

The previous prime is 1513110413. The next prime is 1513110427. The reversal of 1513110421 is 1240113151.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1240113151 = 257 ⋅4825343.

It is a cyclic number.

It is not a de Polignac number, because 1513110421 - 2³ = 1513110413 is a prime.

It is a super-2 number, since 2×1513110421² = 4579006292277594482, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1513110427) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415945 + ... + 419566.

It is an arithmetic number, because the mean of its divisors is an integer number (378486936).

Almost surely, 2^1513110421 is an apocalyptic number.

It is an amenable number.

1513110421 is a deficient number, since it is larger than the sum of its proper divisors (837323).

1513110421 is an equidigital number, since it uses as much as digits as its factorization.

1513110421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 837322.

The product of its (nonzero) digits is 120, while the sum is 19.

The square root of 1513110421 is about 38898.7200432096. The cubic root of 1513110421 is about 1148.0396143157.

Adding to 1513110421 its reverse (1240113151), we get a palindrome (2753223572).

It can be divided in two parts, 15131 and 10421, that added together give a palindrome (25552).

The spelling of 1513110421 in words is "one billion, five hundred thirteen million, one hundred ten thousand, four hundred twenty-one".