Base | Representation |
---|---|
bin | 11100001011110001… |
… | …01001011001010001 |
3 | 1110001111212121012112 |
4 | 32011320221121101 |
5 | 221442031334413 |
6 | 10541240235105 |
7 | 1043651260034 |
oct | 160570513121 |
9 | 43044777175 |
10 | 15131121233 |
11 | 646513a378 |
12 | 2b2346ba95 |
13 | 1571a67c97 |
14 | a377d701b |
15 | 5d85b52a8 |
hex | 385e29651 |
15131121233 has 4 divisors (see below), whose sum is σ = 15146059188. Its totient is φ = 15116183280.
The previous prime is 15131121227. The next prime is 15131121289. The reversal of 15131121233 is 33212113151.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4774395409 + 10356725824 = 69097^2 + 101768^2 .
It is a cyclic number.
It is not a de Polignac number, because 15131121233 - 26 = 15131121169 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15131121199 and 15131121208.
It is not an unprimeable number, because it can be changed into a prime (15131121223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7467458 + ... + 7469483.
It is an arithmetic number, because the mean of its divisors is an integer number (3786514797).
Almost surely, 215131121233 is an apocalyptic number.
It is an amenable number.
15131121233 is a deficient number, since it is larger than the sum of its proper divisors (14937955).
15131121233 is a wasteful number, since it uses less digits than its factorization.
15131121233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14937954.
The product of its digits is 540, while the sum is 23.
Adding to 15131121233 its reverse (33212113151), we get a palindrome (48343234384).
The spelling of 15131121233 in words is "fifteen billion, one hundred thirty-one million, one hundred twenty-one thousand, two hundred thirty-three".
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