Base | Representation |
---|---|
bin | 10110000001001100111… |
… | …101100001100101100001 |
3 | 12100122121220122012002101 |
4 | 112001030331201211201 |
5 | 144242332114404321 |
6 | 3115041222050401 |
7 | 214214342052643 |
oct | 26011475414541 |
9 | 5318556565071 |
10 | 1513119684961 |
11 | 53378a684935 |
12 | 205304879a01 |
13 | ac8c05319c1 |
14 | 53341c6c893 |
15 | 2955e08d791 |
hex | 1604cf61961 |
1513119684961 has 2 divisors, whose sum is σ = 1513119684962. Its totient is φ = 1513119684960.
The previous prime is 1513119684959. The next prime is 1513119684991. The reversal of 1513119684961 is 1694869113151.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1249154934336 + 263964750625 = 1117656^2 + 513775^2 .
It is a cyclic number.
It is not a de Polignac number, because 1513119684961 - 21 = 1513119684959 is a prime.
Together with 1513119684959, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1513119684991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 756559842480 + 756559842481.
It is an arithmetic number, because the mean of its divisors is an integer number (756559842481).
Almost surely, 21513119684961 is an apocalyptic number.
It is an amenable number.
1513119684961 is a deficient number, since it is larger than the sum of its proper divisors (1).
1513119684961 is an equidigital number, since it uses as much as digits as its factorization.
1513119684961 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1399680, while the sum is 55.
The spelling of 1513119684961 in words is "one trillion, five hundred thirteen billion, one hundred nineteen million, six hundred eighty-four thousand, nine hundred sixty-one".
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