151313202513841 has 2 divisors, whose sum is σ = 151313202513842. Its totient is φ = 151313202513840.

The previous prime is 151313202513799. The next prime is 151313202513881. The reversal of 151313202513841 is 148315202313151.

It is an a-pointer prime, because the next prime (151313202513881) can be obtained adding 151313202513841 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 149998806760000 + 1314395753841 = 12247400^2 + 1146471^2 .

It is an emirp because it is prime and its reverse (148315202313151) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 151313202513841 - 2¹⁵ = 151313202481073 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 151313202513794 and 151313202513803.

It is not a weakly prime, because it can be changed into another prime (151313202513881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 75656601256920 + 75656601256921.

It is an arithmetic number, because the mean of its divisors is an integer number (75656601256921).

Almost surely, 2^{151313202513841} is an apocalyptic number.

It is an amenable number.

151313202513841 is a deficient number, since it is larger than the sum of its proper divisors (1).

151313202513841 is an equidigital number, since it uses as much as digits as its factorization.

151313202513841 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 86400, while the sum is 40.

Adding to 151313202513841 its reverse (148315202313151), we get a palindrome (299628404826992).

The spelling of 151313202513841 in words is "one hundred fifty-one trillion, three hundred thirteen billion, two hundred two million, five hundred thirteen thousand, eight hundred forty-one".