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151314120000 = 263254420317
BaseRepresentation
bin1000110011101100000…
…1100011110101000000
3112110120100012201121200
42030323001203311000
54434342403320000
6153302430421200
713634463540621
oct2147301436500
9473510181550
10151314120000
115919896aa3a
12253aa961800
13113658bc364
147476109a48
153e0915d500
hex233b063d40

151314120000 has 210 divisors, whose sum is σ = 541971059058. Its totient is φ = 40350336000.

The previous prime is 151314119981. The next prime is 151314120031. The reversal of 151314120000 is 21413151.

151314120000 is a `hidden beast` number, since 151 + 314 + 1 + 200 + 0 + 0 = 666.

It can be written as a sum of positive squares in 5 ways, for example, as 94047715584 + 57266404416 = 306672^2 + 239304^2 .

It is a super-2 number, since 2×1513141200002 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 29 ways as a sum of consecutive naturals, for example, 149842 + ... + 570158.

Almost surely, 2151314120000 is an apocalyptic number.

151314120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 151314120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (270985529529).

151314120000 is an abundant number, since it is smaller than the sum of its proper divisors (390656939058).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

151314120000 is an equidigital number, since it uses as much as digits as its factorization.

151314120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 420355 (or 420327 counting only the distinct ones).

The product of its (nonzero) digits is 120, while the sum is 18.

Adding to 151314120000 its reverse (21413151), we get a palindrome (151335533151).

The spelling of 151314120000 in words is "one hundred fifty-one billion, three hundred fourteen million, one hundred twenty thousand".